Question

A basketball player, who weighs 600 newtons, jump 0.5 meters vertically off the floor. Calculate her kinetic energy just before hitting the floor.
a)300J
b)3000J
c)9.81m/s^2
d)0

Answer 1

kilograms to newtons is 1 kilogram is 9.81 newtons, so if you divide that by 600? you get close to 0 so I think it's D

Answer 2

Answer:

300 J

Explanation:

$v = \sqrt{2gh}$

$KE = \frac{1}{2}mv^{2}$

——

$v = \sqrt{2(9.81 m/s^{2})(0.5 m)}\\ v = 3.13$

$KE = \frac{1}{2}(61.2 kg)(3.13 m/s)^{2}\\ KE = 300 J$