Question

At a game booth, a student gets a box of candy as the prize for winning a game. The boxes come in four colors: white, red, green, and blue. There are 6 boxes of each color. All the boxes are equally likely to be given away as prizes. Which expression shows the probability of the first winner receiving a white box and the second winner also receiving a box of the same color?

6 over 24 multiplied by 6 over 23
6 over 24 multiplied by 5 over 23
6 over 24 plus 5 over 23
6 over 24 plus 6 over 23

Answer 1

6/24 * 5/23
The first student has a 6/24 chance of picking a white box and with one white box gone there are only 5 white boxes and 23 boxes in total left. In probability you multiply the chances of each pick to get the total probability.

Answer 2

The probability of the first winner receiving a white box and the second winner also receiving a box of the same color $P = \dfrac{6}{24} \times \dfrac{5}{23}$. Option B is correct.

What is the probability?

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

It is Given that the boxes come in four colors: white, red, green, and blue.

Also, there are 6 boxes of each color, which means that there are 6 white boxes, 6 red boxes, 6 green boxes, and 6 blue boxes.

Now, There are 24 boxes in total.

P(receiving a white box for the first pick) = 6/24.

Because there are 6 white boxes over the total amount of boxes to find the probability.

Now, after picking the first white boxes, there are only 5 white boxes left without replacement, which leads to there are also 23 boxes in total left

P(receiving a white box in the second pick) = 5/23.

The probability of the first winner receiving a white box and the second winner also receiving a box of the same color is

6/24×5/23=5/92

Therefore, the probability of the first winner receiving a white box and the second winner also receiving a box of the same color is $P = \dfrac{6}{24} \times \dfrac{5}{23}$

Option B is correct.

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