Question

17. GRAVITY The height above the ground of a ball thrown up with a velocity of 96 feet per second from a height of 6 feet is 6 + 96t - 16t2 feet, where t is the time in seconds. According to this model, how high is the ball after 7 seconds? Explain.

Answer 1

76.23 it would be because 6 + 9060 -62 feet and it says how many seconds that's how I know what it is