Answer:
[tex]\sqrt[3]{373248}=\sqrt[3]{18^{3}*64}\\[/tex]
Step-by-step explanation:
A Perfect Cube is an integer number multiple of three that can be expressed as a product of prime factors raised to 3rd power. We have many Perfect Cubes, such as:
15³=3³x5³, and 15 ∈ ={1,3,6,9,12,15,18,..} so 15 is a perfect cube
18³=2³x3³x3³ and 18 ∈ ={1,3,6,9,12,15,18,..} so 18 is a perfect cube.
Finally, for instance, we can rewrite the number 373248 as
cubic root of 18³ times 64. 18 is a perfect cube 64 is not a perfect cube for 64 =[tex]2^{6}[/tex]
