Question

Use the following table of a school bus during morning pickups to calculate its average speed between 2.8 km and 4.2 km.

Answer 1

To calculate the speed in the mentioned interval, what we must do is calculate the average rate of change.

By definition, the average rate of change is given by:

$AVR = \frac{r(t2) - r(t1)}{t2 - t1}$

Substituting values we have:

$AVR = \frac{4.2 - 2.8}{0.084 - 0.051}$

We rewrite:

$AVR = 42.4 \frac{Km}{h}$

Answer:

The average speed between 2.8 km and 4.2 km of the bus is:

$AVR = 42.4 \frac{Km}{h}$

Answer 2

♡ The Question/Task(s)! ♡  

-According to the table, what is the average speed of the bus between 2.8 km and 4.2 km during morning pickups?  

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♡ The Answer(s)! ♡  

-The answer is 42 km/h!  

I apologize in advance if this answer is incorrect! ♡  

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♡ The Explanation(s)/Step-By-Step! ♡  

-No Explanation/Step-By-Step Provided!  

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♡ Tip(s)! ♡  

-No Tips Provided!