Question

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Xander was traveling at a final velocity of 4.5 m/s for 3.5 seconds. Finley was traveling at a final velocity of 3.6 m/s for 4.2 seconds. Max was traveling at a final velocity of 7.3 m/s for 1.2 seconds. They all started from the same location.
Which lists them from least to most acceleration?
A. Max → Finley → Xander
B. Max → Xander → Finley
C. Xander → Finley → Max
D. Finley → Xander → Max

Answer 1

The answer is D. Finley → Xander → Max because Finley was the slowest and xavier was the fastest

Answer 2

Answer:  D. Finley → Xander → Max

Explanation:

Given

Xander , Finley and Max all started from the same location . So all are having initial velocity zero .

Final velocities are

$V_{xander}=4.5 \frac{m}{s} ,V_{finley}=3.6 \frac{m}{s}, V_{max}=7.3\frac{m}{s}$

Now , Acceleration , $a=\frac{V_{final}-V_{initial}}{t}$

=> Acceleration of Xander , $a_{xander}=\frac{4.5}{3.5}\frac{m}{s^{2}} = 1.29 \frac{m}{s^{2}}$

Acceleration of Finley , $a_{finley}=\frac{3.6}{4.2}\frac{m}{s^{2}} = 0.857 \frac{m}{s^{2}}$

Acceleration of Max , $a_{max}=\frac{7.3}{1.2}\frac{m}{s^{2}} = 6.08 \frac{m}{s^{2}}$

Thus order of their acceleration from least to most is Finley → Xander → Max

=> correct option is D. Finley → Xander → Max