Question

2sinxcosx-sin(2x)cos(2x)=0

A. give the most general solutions to equation
B. simplify the first expression using double angle identity for sine
C. factor the left side of equatioin
D. solve the factored equation

Answer 1

 2sinxcosx = sin(2x)
2sinxcosx-sin(2x)cos(2x)=0
sin(2x)-sin(2x)cos(2x)=0

now factor out sin(2x)
sin(2x)[1 - cos(2x)] = 0
sin(2x) = 0
since
sin(0) = 0
2x = 0
x = 0