Question

Find the sine of both angle A and angle B.

A. sin A = 5/13; sin B = 12/13
B. sin A = 12/13; sin B = 5/13
C. sin A = 5/12; sin B = 12/5
D. sin A = 13/5; sin B = 13/12

Answer 1

sin = opposite/hyp

Sin A = 10/26   = 5/13

Sin b = 24/26 = 12/13

The answer is option A

Hope this helps

Answer 2

Answer:

The correct option is A.

Step-by-step explanation:

Let the third vertex of the triangle be C and the angle C is 90 degree.

In a right angles triangle, the sine ratio is defined as

$\sin \theta=\frac{perpendicular}{hypotenuse}=\frac{opposite}{hypotenuse}$

Using sine ratio,

$\sin A=\frac{BC}{AB}$

$\sin A=\frac{10}{26}$

$\sin A=\frac{5}{13}$

$\sin B=\frac{AC}{AB}$

$\sin B=\frac{24}{26}$

$\sin B=\frac{12}{13}$

Since $\sin A=\frac{5}{13}$ and $\sin B=\frac{12}{13}$, therefore the correct option is A.