Question

The sum of four consecutive multiples of 5 is 110. What is the greatest of the four numbers?

Answer 1

a+b+c+d=110
a=a
b=a+5
c=a+10
d=a+15
a+(a+5)+(a+10)+(a+15)=110
a+a+5+a+10+a+15=110
a+a+a+a+5+10+15=110
4a+30=110
4a=80
a=20
20+15=35 so the greatest of the four numbers is 35

Hope this helps :)