Match the values associated with this data set to their correct descriptions.

{6, 47, 49, 15, 43, 41, 7, 36}

quartile

38.5
median
11
third quartile
10.5
the difference
of the largest
value and the
median
45


Respuesta :

For PLATO Users

FIRST OF ALL MissPhiladelphia Is Clearly INCORRECT

If You Just Want The Answer, Check The Pictures Below

People Who Want To Learn I Explained Step By Step

Given:

[tex]6,7,15,36,41,43,47,49[/tex]

To Find The Median

Use Process Of Elimination

[tex]36,41[/tex]

Then Split Those Numbers Apart

[tex]36,37,38,39,40,41[/tex]

Again Process Of Elimination

[tex]38,39[/tex]

You cannot split these whole numbers

Therefor Your Answer Is

[tex]38.5[/tex]

To Find The Quartiles

[tex]6,7,15,36,41,43,47,49[/tex]

[tex]Median:38.5[/tex]

Put The Given Into Pairs

[tex]\left[\begin{array}{ccc}6&7\\15&36\\41&43\\47&49\end{array}\right][/tex]

Notice There Are 4 EVEN Pairs.

Ever Heard Of The Quote " Read Between The Lines "

There Are Spaces Between Each Of The 4 Pairs

Those Spaces Represent One Quartile

To Find The First Quartile

The First Space Of The EVEN Pairs Is Between 7 and 15

Split Those Numbers

[tex]7,8,9,10,11,12,13,14,15[/tex]

Process Of Elimination

[tex]11[/tex]

The Second Space Of The EVEN Pairs Is Actually The Median

To Find The Third Quartile

The Third Space Of The EVEN Pairs Is Between 43 and 47

Split Those Numbers

[tex]43,44,45,46,47[/tex]

Process Of Elimination

[tex]45[/tex]

To Find The Difference Of The Largest Value And Median

[tex]6,7,15,36,41,43,47,49[/tex]

[tex]Median:38.5[/tex]

[tex]Q1:11[/tex]

[tex]Q3:45[/tex]

The Median We All Know Is [tex]38.5[/tex]

The Largest Value Is [tex]49[/tex]

Subtract The Numbers

[tex]\left[\begin{array}{ccc}49-38.5\end{array}\right][/tex]

[tex]10.5[/tex]


Ver imagen dakotacsey03
Ver imagen dakotacsey03

Answer:

Step-by-step explanation:

median is 38.5

first quartile is 11

the third quartile is 45

and the difference is 10.5

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