Respuesta :
You take the mass of carbon dioxide, 56.8g, divide by its molar mass, 44.01g/mol, to produce the moles of carbon dioxide. This is multiplied by the molar ratio of butane/CO2, (2/8) = 1/4, which gives the moles of butane required to produce the carbon dioxide.
The mass of a substance is the product of the moles and the molar mass. 65.5 g of carbon dioxide will be able to produce 21.62 grams of butane.
What is mass?
The mass of a reactant or a product is estimated by the number of moles and the molar mass of the substance.
The combustion reaction of methane is shown as,
2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O
Given,
Molar mass of butane = 58.12 g/mol
Mass of carbon dioxide = 65.5 g
Molar mass of carbon dioxide = 44.01 g/mole
Moles of carbon dioxide are calculated as,
Moles = mass ÷ molar mass
= 65.5 ÷ 44.01
= 1.488 moles
From the above reaction, two moles of butane produce eight moles of carbon dioxide. So, 1.488 moles of carbon dioxide will be produced from,
2 × 1.488 ÷ 8 = 0.372 moles
The moles of butane required is 0.372 moles
The mass of butane from moles is calculated as,
Mass = moles × molar mass
= 0.372 × 58.12 g/mole
= 21.62 gms
Therefore, 21.62 gm of butane is required to produce 65.5 g of carbon dioxide.
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