Question

b) Here are the first four terms of another sequence.
6 11 16 21
Write an expression for the nth term of this sequence.

Answer 1

Answer:

        aₙ = 5n + 1

Step-by-step explanation:

11 - 6 = 5  ,   16 - 11 = 5  ,  21 - 16 = 5

So, it's atithmetic formula with common difference os 5

$a_n = a_1+d(n-1)\\\\a_1=6\\d=5\\\\a_n=6+5(n-1)\\\\a_n=6 +5n-5\\\\a_n = 5n+1$