Question

1. In the equation
12 + 5C12 + 6H20-→ 2HIO; + 10HCI
(a) has iodine been oxidized, or has it been reduced?
(b) has chlorine been oxidized, or has it been reduced?
(Figure 17.2)
12.1

Answer 1

Answer: iodine is oxidised and Chlorine is reduced

Explanation: iodine is oxidised, in I2 oxidation number sim 0,

in HIO oxidation number is +I.

Chlorine is reduced, oxidation number changes from 0 to -I