Question

When a 6 Ω resistor is connected across the terminals of a 3 V battery, the number of coulombs passing through the resistor per second is

Answer 1

Answer:

Given that - R = 6 ohm

V = 3 volt

n = ?

so by ohms law , V = I X R

I = V \ R = 3 \ 6 = 0.5 A

we know that I = Q / T here t is 1 sec

Q = I X T = 0.5 X 1 = 0.5 C

By the law of quantization ,

Q = n x e

n = Q / e = 0.5 / 1.6 x 10 ^-19

n = 0.3125 x 10^19

hoped so u got the answer mark me as brainellist :)

Answer 2

Answer:

0.5/1.6×10^-19

Explanation:

formula for current is v

I R

3/6=0.5

charge if found by the product of current and time which is one second

0.5×1 =0.5

deficiency of n=no of charges×charge of electrons

0.5/1.6×10^-19