Question

Use a Venn diagram to answer.
If n(A) = 8, n(B) = 9 and n(An B) = 6, what is n(AUB)?

Answer 1

Answer:

$n(A \cup B) = 6$

Step-by-step explanation:

In Venn sets, we have that:

$n(A \cup B) = n(A) + n(B) - n(A \cap B)$

In which n is the number of elements that each set contains.

In this question:

$n(A) = 8, n(B) = 9, n(A \cap B) = 6$

So

$n(A \cup B) = n(A) + n(B) - n(A \cap B) = 8 + 9 - 6 = 17 - 6 = 11$

So

$n(A \cup B) = 6$