Question

2. A 0.02 kg ball spins in a horizontal circle of radius 0.50 m with a frequency
of 4.0 Hz. What is the tension force in the string (the centripetal force on
the ball)?

Answer 1

The tension force in the string will be "6.3 N".

Given:

• Frequency, f = 4.0 Hz
• Mass, m = 0.02 kg
• Radius, r = 0.50 m

We know,

→ $W = 2 \pi f$

By substituting the values,

        $= 2 \pi \times 4.0$

        $= 8 \pi \ rad/s$

hence,

→ $T = m \omega^2 R$

       $= 0.02(8 \pi)^2 (0.50)$

       $= 6.31654 \ N$

or,

       $= 6.3 \ N$  

Thus the answer above is right.

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