The half-life of argon-39 is 269 years. It decays into krypton-39. After 1,076 years, what fraction of the original amount of argon-
1/16
1/4
1/2
1/8

Respuesta :

Answer:

The correct answer is - 1/16.

Explanation:

The half-life is the time that is required to decay nuclei to the half amount of its original amount in a radioactive sample. It is represented by the t1/2. The time that is required to reduce to half of its initial value is known as the half-life of a particular sample.

Half-life of argon-39 = 269 years

total time is taken in complete decay = 1076 years

Number of half-lives required = 1076/269

= 4

So the original amount of the sample = (1/2)^n

n = number of half-life

= 1/2^4

= 1/16

The correct answer is = 1/16

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