Answer: cage I
Step-by-step explanation:
Given
43 gm of copper and 7 gram of other metal
Another cage has 83 gram of copper and 17 gm of other metals
Here, the percentage of copper is
For the first case
[tex]\Rightarrow \dfrac{43}{43+7}\times 100=86\%[/tex]
For the second case
[tex]\Rightarrow \dfrac{83}{83+17}\times 100=83\%[/tex]
So, the cage-I has more percentage of copper