Question

A toy rocket is launched from a platform 33 feet above the ground at a speed of 83 feet per second. The height
of the rocket in feet is given by the polynomial -167 + 83t + 33, where t is the time in seconds. How high will
the rocket be after 3 seconds?
HELP ASAP

Answer 1

Answer:

138 feet

Step-by-step explanation:

plug "3" into the expression by replacing "t" with "3"

-16t^2+83t+33

-16(3)^2+83(3)+33 (remember PEMDAS)

=-16(9)+249+33

=-144+282

=138 (I hope this helps)