Question

Consider the line y=7x+4.
Find the equation of the line that is parallel to this line and passes through the point ( -3, 5)
Find the equation of the line that is perpendicular to this line and passes through the point ( -3, 5)

Answer 1

Answer:

parallel y=7x+26

perpendicular y=1/7x+32/7

Step-by-step explanation:

parallel line have the same slope

y-5=7(x-(-3))

y-5=7(x+3)

y-5=7x+21

y=7x+21+5

y=7x+26

perpendicular slope  is the opposite of the original slope of 7

y-5=-1/7(x-(-3))

y-5=-1/7(x+3)

y-5=-1/7x-3/7

y=-1/7x-3/7+5

y=-1/7x+32/7