Question

Using a force of 12.0 Newtons, a student pulls a 50.0 Newton weight along the tabletop for a distance of 10.0 meters in
4.0 seconds. Compute the power developed by the student.
Remember to include your data, equation, and work when solving this problem

Answer 1

Answer:30watt

Explanation:  Force applied by student F = 12 N

Displacement s = 10 m

Time t = 4 s

Work done W = Fs

Power P = W/t = Fs/t

= 12 * 10/4 Watt

= 30 Watt

Answer 2

The power developed by the student is 30 Watt.

To find the value of power the given values are,

Force applied by the student F = 12 Newton,

Distance s = 10 meters,

Weight pulled by the students = 50 Newton,

Time t = 4 seconds.

How work done and power are related to one another?

Work done:

  The product of displacement of an object and the component of the applied force which is in the direction of the object's displacement is said to be Work done.

      It's unit is kg⋅m²⋅s⁻² or Joules.

  Work done W = Force ( F ) × Distance ( S )

                          = 12 × 10

                          = 120 J.

Power:

  Power can be defined as the ratio of work done to time interval.

                 $P = \frac{W}{\Delta t}$

 It's unit is Watt.

  Power , P = 120 / 4

                P = 30 Watt.

Thus, the power developed by the student is 30 watt.

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