Question

The picture shows a barn door.



What is the length of the bar AC?

6 sin 60°

6 cos 60°

Answer 1

SOH, CAH, TOA

sin=oposite/hypotonuse
cos=adjacent/hyptonuse

sin60=CB/6, we want AC

cos60=AC/6
then times 6 both sides
6cos60=ac

answer is 6cos60

Answer 2

Answer:

Option B is correct.

Length of the bar AC i.e

$AC = 6 \cos 60^{\circ}$

Step-by-step explanation:

As per the statement:

In right angle triangle ACB

Side AB = 6 feet and $\angle A = 60^{\circ}$

We have to find the length of bar AC:

Using cosine function ratio:

$\cos \theta = \frac{\text{Adjacent Side}}{\text{Hypotenuse side}}$

Here,

Adjacent side= AC

Hypotenuse side = AB = 6 feet

$\cos A = \frac{\text{AC}}{\text{AB}}$

then;

substitute the given values we have;

$\cos 60^{\circ} = \frac{\text{AC}}{6}$

Multiply both sides by 6 we have;

$AC = 6 \cos 60^{\circ}$

Therefore, the length of the bar $AC = 6 \cos 60^{\circ}$