Question

What is the empirical formula for a compound that has 1.5 moles of copper and 0.5 moles of phosphorus?

Answer 1

Answer:

$Cu_{3}P$

Explanation:

usually, the first step is to calculate the moles but since that is already given in the question we can move onto the next step

least molar ratio:

Cu =  $\frac{1.5}{0.5}$ = 3

P = $\frac{0.5}{0.5}$ = 1

thus, empirical formula = $Cu_{3}P$

Answer 2

The empirical formula for a compound that has 1.5 moles of copper and 0.5 moles of phosphorus is Cu₃P.

What is the empirical formula?

Empirical formula of any compound gives idea about the number of constituents particles present in that compound by mentioning the ration.

In the question, given that:

Moles of copper = 1.5 moles

Moles of phophorous = 0.5 moles

Now we divide the given moles by the smallest number to get the ration number as follow:
Cu  :  P

1.5/0.5  :  0.5/0.5

3  :  1

Hence, required empirical formula is Cu₃P.

To know more about empirical formula, visit the below link:

https://brainly.com/question/1603500