Question

What is an equation of the line that passes through the point (6,-2)(6,−2) and is parallel to the line 5x+3y=65x+3y=6?

Answer 1

Answer:

I need sum more detail

Step-by-step explanation:

Answer 2

Answer:

y=(-5/3)x+8

Step-by-step explanation:

Rearrange 5x+3y=6 in slope-intercept form

y=mx=b

5x+3y=6

3y=6-5x

y=2-(5x)/3

then slope for a line parallel is -5/3

Use point slope form y-y1=m(x-x1)

plug in values of (x,y) = (6,-2)

and m=-5/3

y-y1=m(x-x1)

y-(-2)=(-5/3)(x-6)

y+2=(-5/3)x+10

y=(-5/3)x+10-2

y=(-5/3)x+8