Answer:
h = 1.01 x 10⁻³⁴ J.s
Explanation:
The energy applied by the voltage must be equal to the energy associated with the wavelength of light:
[tex]eV = \frac{hc}{\lambda}\\[/tex]
where,
e = charge on electron = 1.6 x 10⁻¹⁹ C
V = stopping potential
h = Planck's Constant = ?
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of light
For λ = 400 nm = 4 x 10⁻⁷ m, V = 0.7 V:
[tex](1.6\ x\ 10^{-19}\ C)(0.7\ V) = \frac{h(3\ x\ 10^8\ m/s)}{4\ x\ 10^{-7}\ m}\\[/tex]
h = 1.49 x 10⁻³⁴ J.s
For λ = 500 nm = 5 x 10⁻⁷ m, V = 0.2 V:
[tex](1.6\ x\ 10^{-19}\ C)(0.2\ V) = \frac{h(3\ x\ 10^8\ m/s)}{5\ x\ 10^{-7}\ m}\\[/tex]
h = 0.53 x 10⁻³⁴ J.s
Taking average of both values:
[tex]h = \frac{(0.53+1.49)\ x\ 10^{-19}\ J.s}{2}[/tex]
h = 1.01 x 10⁻³⁴ J.s