Respuesta :

In order to calculate the amount of heat energy required to melt 347 grams of ice, we need to will apply the equation:
Q = ml, where m is the mass of substance and l is its latent heat of fusion. For ice, the latent heat of fusion is 334 joules per gram. Therefore:
Q = 347 x 334
Q = 112,558 joules of energy

[tex]$\boxed{115.898{\text{ kJ}}}$[/tex] of heat is required to completely melt 347 g ice.

Further explanation:

Latent heat  

The heat released or absorbed during the process of conversion physical state of a substance without altering the temperature is known as the latent heat.

The latent heat of fusion of ice is 334 J/g.

When the physical state changes from the solid phase to liquid phase then the amount of heat absorbed in this process to completely convert the solid into liquid without altering the temperature is known as the latent heat fusion.

The formula to calculate heat absorbed from latent heat of fusion is,

[tex]${\text{q}}={\text{m}}{{\text{H}}_{\text{f}}}$[/tex]           …… (1)

Here,

q is heat absorbed.

m is mass of substance.

[tex]${{\text{H}}_{\text{f}}}$[/tex] is latent heat of fusion.

The mass of given ice is 347 g.

Substitute 347 g for m and 334 J/g for [tex]${{\text{H}}_{\text{f}}}$[/tex] in equation (1).

[tex]$\align{{\text{q}}&={\text{m}}{{\text{H}}_{\text{f}}}\cr&=\left( {347{\text{ g}}} \right)\left({334{\text{ J/g}}}\right)\cr&=115898{\text{ J}}\cr}$[/tex]

Learn more:

1. The difference between heat and temperature.:https://brainly.com/question/914750

2. Determine the process by which water enters into atmosphere?: https://brainly.com/question/2037060

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Thermodynamics

Keywords: Latent, Heat, fusion, Latent heat of fusion, temperature, ice, water, vapors, equilibrium, heat required, melting, heat release, heat absorbed, 115.898 kJ.

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