Answer: 0
Step-by-step explanation:
Don't forget:
[tex]\lim_{x\to \infty} \frac{1}{x} = 0[/tex]
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[tex]x^2>(5-cosx)[/tex]
[tex]x^2[/tex] is greater than cosx ,so we have to evaluate [tex]\frac{1}{x^2}[/tex]
[tex]\lim_{x\to \infty} \frac{1}{x^2} \\\\0[/tex]
