Answer:
C₃H₈O
Explanation:
From the question given above, the following data were obtained:
Mass of Carbon (C) = 0.599 g
Mass of Hydrogen (H) = 0.134 g
Mass of Oxygen (O) = 0.266 g
Empirical formula =?
The empirical formula of the compound can be obtained as follow:
C = 0.599 g
H = 0.134 g
O = 0.266 g
Divide by their molar mass
C = 0.599 / 12 = 0.050
H = 0.134 / 1 = 0.134
O = 0.266 / 16 = 0.017
Divide by the smallest
C = 0.050 / 0.017 = 3
H = 0.134 / 0.017 = 8
O = 0.017 / 0.017 = 1
Empirical formula => C₃H₈O
