Find the average rate of change of y=log3⁡ x over the interval 1≤x≤3. Write your answer as a fraction in the simplest form.

Respuesta :

Answer:

If the interval is 1 < x < 3, then you are examining the points (1,4) and (3,16). From the first point, let a = 1, and f (a) = 4. From the second point, let b = 3 and f (b) = 16. The average rate of change is 6 over 1, or just 6.

The average rate of change is [tex]\frac{6}{25}[/tex]

What is rate of change over an interval?

'When we calculate average rate of change of a function over a given interval, we’re calculating the average number of units that the function moves up or down, per unit along the x-axis. We could also say that we’re measuring how much change occurs in our function’s value per unit on the x-axis.'

According to the given problem,

Rate of change formula = [tex]\frac{f(b) - f(a)}{b-a}[/tex]

y = log3x

⇒ a= 1

   b= 3

Therefore,

⇒ [tex]\frac{log(3*3) - log(3*1)}{3-1}[/tex]

⇒ [tex]\frac{log9 - log3}{2}[/tex]

⇒[tex]\frac{1}{2}[/tex] log[tex](\frac{9}{3})[/tex]

⇒ [tex]\frac{1}{2}[/tex] * log 3

⇒ [tex]\frac{6}{25}[/tex]

Hence we can conclude the rate of change as [tex]\frac{6}{25}[/tex]

Learn more about rate of change here: https://brainly.com/question/18193470

#SPJ2

ACCESS MORE