Question

Two vehicles are approaching an intersection. One is a 2600 kgkg pickup traveling at 17.0 m/sm/s from east to west (the −x−x- direction), and the other is a 1300 kgkg sedan going from south to north (the +y−+y− direction at 24.0 m/sm/s ). Part A Find the xx -component of the net momentum of this system. pxpx = nothing kg⋅m/skg⋅m/s SubmitRequest Answer Part B Find the yy-component of the net momentum of this system. pypy = 0 kg⋅m/skg⋅m/s SubmitPrevious AnswersRequest Answer Incorrect; Try Again; 4 attempts remaining Part C What is the magnitude of the net momentum?

Answer 1

Answer:

a) the x-component of the net momentum is 44200 kgm/s $(-x)$

b) the y-component of the net momentum is 31200 kgm/s $(y)$

c) the magnitude of the net momentum is 54102.5 kgm/s

Explanation:

Given the data in the question;

a) x-component of the net momentum of this system.

the second vehicle ( sedan ) doesn't have momentum along x-axis, the momentum along x-axis is strictly contributed by the pick up

so;

Px = 2600 kg × 17.0 m/s $(-x)$

Px = 44200 kgm/s $(-x)$

Therefore, the x-component of the net momentum is 44200 kgm/s $(-x)$

b) y-component of the net momentum of this system

Also, momentum along y-axis is entirely provided by the sedan

Py = 1300 kg × 24.0 m/s $(y)$

Py = 31200 kgm/s $(y)$

Therefore, the y-component of the net momentum is 31200 kgm/s $(y)$

c) magnitude of the net momentum?

magnitude of the net momentum P = √( Px² + Py² )

so we substitute  

P = √( (44200)² + (31200)² )

P = √( 2927080000 )

P = 54102.5 kgm/s

Therefore, the magnitude of the net momentum is 54102.5 kgm/s