Question

Un móvil sale con una rapidez de 5m/s y alcanza una rapidez de 40m/s en 10s. Determine la distancia recorrida.

Answer 1

Answer:

d = 225 m

Step-by-step explanation:

Initial speed, u = 5 m/s

Final speed, v = 40 m/s

Time, t = 10 s

Acceleration,

$a=\dfrac{v-u}{t}\\\\a=\dfrac{40-5}{10}\\\\a=3.5\ m/s^2$

Let d is the distance covered. Using second equation of motion to find it i.e.

$d=ut+\dfrac{1}{2}at^2\\\\d=5\times 10+\dfrac{1}{2}\times 3.5\times 10^2\\\\d=225\ m$

So, it will cover 225 m.