Question

PART1
Simplify completely: the quantity 5 times x to the third power plus 10 times x to the 2nd power plus 15 times x all over 5 times x

a.x^2 + 10x^2 + 15x

b.2x + 6

c.x^2 + 2x + 3

d.x^4 + 2x^3 + 3x^2



PART2
Simplify completely: the quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x

a.the quantity 3 times x to the third power plus 5 times x plus 2 all over x

b.3x^3 + 5x + 2

c.3x^2 + 5x^2 + 2x

d.3x^5 + 5x^3 + 2x^2

Answer 1

P1. The answer is c.x^2 + 2x + 3

the quantity 5 times x to the third power plus 10 times x to the 2nd power plus 15 times x all over 5 times x is: $\frac{5 x^{3}+10x^{2}+15x }{5x}$

$\frac{5 x^{3}+10x^{2}+15x }{5x} =\frac{5x* x^{2}+5x*2x+5x *3}{5x}= \frac{5x( x^{2} +2x+3)}{5x} = x^{2} +2x+3$


P2. The answer is b.3x^3 + 5x + 2

the quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x is: $\frac{3 x^{4}+5 x^{2} +2x }{x}$

$\frac{3 x^{4}+5 x^{2} +2x }{x} = \frac{x*3 x^{3} +x*5x+x*2}{x} = \frac{x(3 x^{3} +5x+2)}{x} =3 x^{3} +5x+2$

Answer 2

Answer: cccccc

Step-by-step explanation: