If line WP is a median and an angle bisector, AP = 3y+11, PH = 7y - 5, angle HWP = x +12, angle PAW = 3x - 2, and angle HWA = 4x - 16, find x and y. Is WP also an altitude? Explain.
∠ HWA / 2 = ∠HWP ( 4 x - 16 ) / 2 = x + 12 4 x - 16 = 2 x + 24 2 x = 40 x = 20 AP = PH 3 y + 11 = 7 y - 5 16 = 4 y y = 4 ∠PAW = 60 - 2 = 58° ∠PWA = 32°, ∠PWH = 32° ∠AWH = 64° ∠WHA = 58° Therefore Δ AWH is isosceles. Line WP is an altitude because it bisects the base of an isosceles triangle.
