Two rockets having the same acceleration start from rest, but the first rocket travels for twice as much time as the second one. If rocket A goes for 310 km, how far will B go? If rocket A reaches a speed of 320 , what speed will rocket B reach?
Let ta be the time the first rocket travels and tb be the time the second rocket travels. ta = 2tb We apply: sa = ut + 1/2 at², with u = 0 since they start from rest. 310000 = 1/2a(ta)² a = 620000 / 4(tb)²
sb = 1/2 a(tb)² sb = 1/2 x 620000 / 4(tb)² x (tb)² sb = 77.5 Km
We apply v = u + at, with u = 0 va = a(ta) a = 320/2(tb)
