Respuesta :
The answer is 11x² + 0.7x + 8.2
Total number of white-sided and black-tailed jackrabbits is the sum of their polynomials:
5.5x² – 9.2x + 6.9 + 5.5x² + 9.9x + 1.3 = 5.5x² + 5.5x² – 9.2x + 9.9x + 6.9 + 1.3 =
= 11x² + 0.7x + 8.2
Total number of white-sided and black-tailed jackrabbits is the sum of their polynomials:
5.5x² – 9.2x + 6.9 + 5.5x² + 9.9x + 1.3 = 5.5x² + 5.5x² – 9.2x + 9.9x + 6.9 + 1.3 =
= 11x² + 0.7x + 8.2
Answer: [tex]11x^2+0.7x+8.2[/tex]
Step-by-step explanation:
Given: A biologist studied the populations of white-sided jackrabbits and black-tailed jackrabbits over a 5-year period. The biologist modeled the populations, in thousands, with the following polynomials where x is time, in years.
white-sided jackrabbits: [tex]5.5x^2-9.2x+6.9[/tex]
black-tailed jackrabbits:[tex]5.5x^2+9.9x+1.3[/tex]
The polynomial models the total number of white-sided and black-tailed jackrabbits is given by :-
[tex]5.5x^2-9.2x+6.9+5.5x^2+9.9x+1.3[/tex]
Combining like terms we get,
[tex]=5.5x^2+5.5x^2-9.2x+9.9x+6.9+1.3[/tex]
[tex]=(5.5+5.5)x^2+(-9.2+9.9)x+8.2\\\\=11x^2+0.7x+8.2[/tex]
Hence, the polynomial models the total number of white-sided and black-tailed jackrabbits is [tex]11x^2+0.7x+8.2[/tex]