Question

Find the diagonal of the rectangular solid with the given measures.

l = 3, w = 3, h = 2

Answer 1

The answer is √22 ≈ 4.69

The diagonal (d) of the rectangular solid with length l, width w, and height h is:
d = √(l² + w² + h²)
l = 3
w = 3
h = 2

d = √(3² + 3² + 2²) = √( 9 + 9 + 4) = √22 ≈ 4.69

Answer 2

Answer: Diagonal of the rectangular solid is 4.69 units.

Step-by-step explanation:

Since we have given that

Length of rectangular solid (l)= 3

Width of a rectangular solid (w) = 3

Height of rectangular solid (h) = 2

As we know the formula for the diagonal of the rectangular solid:

$D=\sqrt{l^2+w^2+h^2}\\\\D=\sqrt{3^2+3^2+2^2}\\\\D=\sqrt{9+9+4}\\\\D=\sqrt{22}\\\\D=4.69\ units$

Hence, diagonal of the rectangular solid is 4.69 units.