Respuesta :
Correct answer is B.
[tex](2.7,5.1)\Rightarrow x_1=2.7,y_1=5.1 \\(3,4.7)\Rightarrow x_2=3,y_2=4.7 \\ \\d= \sqrt{(3-2.7)^2+(4.7-5.1)^2}= \sqrt{0.3^2+(-0.4)^2} = \sqrt{0.09+0.16} \\ \\d= \sqrt{0.25}=0.5 [/tex]
[tex](2.7,5.1)\Rightarrow x_1=2.7,y_1=5.1 \\(3,4.7)\Rightarrow x_2=3,y_2=4.7 \\ \\d= \sqrt{(3-2.7)^2+(4.7-5.1)^2}= \sqrt{0.3^2+(-0.4)^2} = \sqrt{0.09+0.16} \\ \\d= \sqrt{0.25}=0.5 [/tex]
