Question

Reaction is
CO2(g) + C(s) <=> 2CO(g)
Kp = 5.7, 1200K

Calcualte the total pressure at equilibrium when 4.45g CO2 is introduced into a 10.0L container and heated to 1200K in the presence of 2.00g of graphite

Answer 1

According  to the task, you  are proveded with patial pressure of CO2 and graphite, and here is complete solution for the task :
At first you have to find n1 =moles of CO2 and n2 which are moles of C 
The you go :
$CO2(g) + C(s) \ \textless \ =\ \textgreater \ 2CO(g)$

n1 n2 0
-x -x +2x
$n1-x n2-x 2x Kp=P^2 (CO)/Pco2$
After that you have to use the formula $PV=nRT$
 $Kp=(2x)^2/n1-x$
Then you have to solve x, and for that you have to use RT/V
And to find total values:$P(total)=n(total)*R*T/V$
I am absolutely sure that this would be helpful for you.