Respuesta :
Given,
Diameter of the basketball = 9.4 inches
∴ Radius of the basketball = diameter ÷ 2 = 9.4 ÷ 2 = 4.7 inches
π = 3.14159
Surface area of the basketball is the surface area of the sphere = 4 π r² = 4 × 3.141 x 4.7² = 277.59 = 277.6 inches²
Diameter of the basketball = 9.4 inches
∴ Radius of the basketball = diameter ÷ 2 = 9.4 ÷ 2 = 4.7 inches
π = 3.14159
Surface area of the basketball is the surface area of the sphere = 4 π r² = 4 × 3.141 x 4.7² = 277.59 = 277.6 inches²
SA=4pir^2
d/2=r
9.4/2=r=4.7
SA=4*3.141592*4.7^2
SA=227.591
answer is D
d/2=r
9.4/2=r=4.7
SA=4*3.141592*4.7^2
SA=227.591
answer is D