Question

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$\underline{ \underline{ \text{QUESTION : }}}$ In the given quadrilateral PQRS, the mid-points of the sides PQ , QR , RS and SP are A , B , C and D respectively. Prove that ABCD is a parallelogram.

Answer 1

Answer:

See Below.

Step-by-step explanation:

We are given that A, B, C, and D are the midpoints of sides PQ, QR, RS, and SP, respectively.

And we want to prove that ABCD is a parallelogram.

By the definition of midpoint, this means that:

$SD\cong DP, \, PA\cong AQ, \, QB\congBR, \, \text{ and } RC\cong CS$

To prove, we can construct a segment from S to Q to form SQ. This is shown in the first diagram.

By the Midpoint Theorem:

$DA\parallel SQ$

Similarly:

$CB\parallel SQ$

By the transitive property for parallel lines:

$DA\parallel CB$

Likewise, we can do the same for the other pair of sides. We will construct a segment from P to R to form PR. This is shown in the second diagram.

By the Midpoint Theorem:

$AB\parallel PR$

Similarly:

$DC\parallel PR$

So:

$AB\parallel DC$

This yields:

$DA\parallel CB\text{ and } DC\parallel AB$

By the definition of a parallelogram, it follows that:

$ABCD\text{ is a parallelogram.}$

Answer 2

Answer:

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