We have that the grams of iron contained 4.06X10^24 atoms of iron is
g= 376.6g
From the question we are told
How many grams of iron contain 4.06X10^24 atoms of iron?
Generally the equation for the Moles of Iron is mathematically given as
[tex]M=\frac{4.06x10^24}{6.02x10^23} \\\\M=6.744moles[/tex]
Therefore
Where Molar mass of Iron =55.845
Generally the equation for the mass is mathematically given as
g= 6.744 x 55.85
g= 376.6g
Therefore
the grams of iron contained 4.06X10^24 atoms of iron is
g= 376.6g
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