Question

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=22°, and DB = 44 feet. Find the length of BC to the nearest tenth of a foot.

Answer 1

Answer: 47.5 ft

Step-by-step explanation:

since this is a right triangle, you can use trig to solve for x:

cos 22° = $\frac{44}{x}$ (cos = adjacent/hypotenuse)

x * cos 22° = 44

x = $\frac{44}{cos 22}$ (plug into calc)

x = 47.5 ft