Respuesta :
Answer:
Trapezoid area:
- A = 1/2(a + b)h, where a, b - bases , h - height
17. a)
- a = RS = 4 units
- b = AT = 8 units
- h = 8 units, the distance between RS and AT
A = 1/2(4 + 8)*8 = 48 units²
17. b)
- a = SK = 4 units
- b = OC = 10 units
- h = SO = 6 units
A = 1/2(4 + 10)*6 = 42 units²
18. a)
- a = ME = 6 units
- b = AZ = 10 units
- h = MA = 8 units
A = 1/2(6 + 10)*8 = 64 units²
Area of trapezoid:
Line RS: 2x2 = 4 units (first base)
Line TA: 4x2 = 8 units (second base)
The height (aka that x-axis inside shape): 4x2 = 8 units (h)
Area formula: (4 + 8)8 ÷ 2
= (4 + 8)8 ÷ 2
= 12(8) ÷ 2
= 96 ÷ 2
ANSWER = 48 sq. units
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Area of trapezoid:
Line SK: 2x2 = 4 units (first base)
Line OC: 5x2 = 10 units (second base)
Line SO (height): 3x2 = 6 units (h)
Area formula: (b1 + b2)h ÷ 2
= (4 + 10)6 ÷ 2
= 14(6) ÷ 2
= 84 ÷ 2
ANSWER = 42 sq. units
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Area of trapezoid:
Line ME: 6 units (first base)
Line AZ: 10 units (second base)
Line MA (height): 8 units (h)
Area formula: (b1 + b2)h ÷ 2
= (6 + 10)8 ÷ 2
= (16)8 ÷ 2
= 128 ÷ 2
= 64
ANSWER = 64 sq. units