Question

Below is a simple set of weights obtained while immersing potato slices in various sugаr solutions over 60 minutes.
Time OM sucrose 0.4M sucrose 0.6M sucrose (min) 0.8 M sucrose 1.0M sucrose
(min)
0 4.36 g 4.59 g 4.7g 4.5 g 5.0 g
30 4.5 g 4.3 g 4.4 g 4.1 g 4.6 g
60 4.68 4.28 4.0 g 3.7 g 4.08
For each solution, calculate the rate of weight change over this 60-minute period.
Using the osmosis data in the question above, determine the percent weight change for each sucrose solution.
0.0M sucrose = %
0.4M sucrose = %
0.6M sucrose = %
0.8M sucrose = %
1.0M sucrose = %

Answer 1

Answer:

Explanation:

The rate of weight change can be determined by using the formula:

weight change = weight at the final time - weight at the initial time.

Molarity                     Weight change

0.0M sucrose  →        (4.68 - 4.36)  =  0.32  g/min

0.4 M sucrose →         (4.28 - 4.59) =  - 0.31  g/min

0.6 M sucrose →         (4.0 - 4.7)      =  - 0.7   g/min

0.8 M sucrose →         (3.7 - 4.5)      = - 0.8    g/min

1.0 M sucrose  →         (4.08 - 5.0)   = - 0.92  g/min

Percent weight change = $\dfrac{\text{final weight - Initial weight}}{Initial \ weight } \times100$

Now;

Molarity                     Weight change

0.0M sucrose  →           $\dfrac{0.32}{4.68}\times 100$   =   6.8 %

0.4 M sucrose →           $\dfrac{0.31}{4.59} \times 100$    = 8.4 %

0.6 M sucrose →           $\dfrac{0.70}{4.7} \times 100$     = 14.8 %

0.8 M sucrose →         $\dfrac{0.80}{4.5}\times 100$       = 17 %

1.0 M sucrose  →         $\dfrac{0.92}{5}\times 100$        = 18.4%