Question

A soccer ball on the ground is kicked with an initial velocity of 37 feet per second at an elevation angle of 70°. Which parametric equations represent the path of the soccer ball?

A: x(t) = 37cos(70o)t and y(t) = –16t2 + 37sin(70o)t
B: x(t) = 37sin(70o)t and y(t) = –16t2 + 37cos(70o)t
C: x(t) = 37cos(70o)t and y(t) = –16t2 + sin(70o)t + 37
D: x(t) = 37sin(70o)t and y(t) = –16t2 + cos(70o)t + 37

Answer 1

Answer: It’s A

Step-by-step explanation: Got it right on the quiz edg2021

Answer 2

The parametric equations represent the path of the soccer ball is

$x = 37cos(70)t$  and $y = 37sin(70)t - 16t^{2}$

What is projectile motion?

Projectile motion is the motion of an object thrown or projected into the air, subject to only the acceleration of gravity. The object is called a projectile, and its path is called its trajectory.

projection motion formula :

Position at time t

x = ($v_{0}$ cosθ)t  

y = ($v_{0}$ sinθ)t – 1/2 g$t^{2}$  

According to the question

A soccer ball on the ground is kicked

initial velocity ($v_{0}$)= 37 feet per second

elevation angle = 70°

using projection motion formula :

Position at time t

g = 9.8 m/$sec^{2}$ = 32 ft/$sec^{2}$

x = ($v_{0}$ cosθ)t  

$y = v_{0} sin$θ$t$$-\frac{1}{2} gt^{2}$

substituting the value $v_{0}= 37$ and θ = 70 degrees in the above formula

$x = 37cos(70)t$ 

$y= 37sin(70)t -\frac{1}{2} ( 32)t^{2}$

$y = 37sin(70)t - 16t^{2}$

Hence,  the parametric equations represent the path of the soccer ball is

$x = 37cos(70)t$  and

$y = 37sin(70)t - 16t^{2}$

To know more about projectile motion here:

https://brainly.com/question/11049671

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