Question

Does anybody know the right answer?

Answer 1

Given:

A line passes through the points (9,9) and $(x_2,-1)$.

The slope of the line is $\dfrac{5}{6}$.

To find:

The value of $x_2]$.

Solution:

Slope formula:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

The line passes through the points (9,9) and $(x_2,-1)$. So, the slope of the line is:

$m=\dfrac{-1-9}{x_2-9}$

$m=\dfrac{-10}{x_2-9}$

It is given that the slope of the line is $\dfrac{5}{6}$.

$\dfrac{5}{6}=\dfrac{-10}{x_2-9}$

$5(x_2-9)=-10(6)$

$5x_2-45=-60$

$5x_2=-60+45$

$5x_2=-15$

Divide both sides by 5.

$x_2=-\dfrac{15}{5}$

$x_2=-3$

Therefore, the value of $x_2$ is $-3$.