Respuesta :

Answer:

The formula is dimensionally correct.

Explanation:

Given

[tex]s = ut + \frac{1}{2}at^2[/tex]

Required

Prove its correctness

Write out the dimension of each:

[tex]s = M^0LT^0[/tex] --- displacement

[tex]ut = M^0LT^{-1} * T[/tex] --- velocity * time

[tex]\frac{1}{2}at^2 = M^0LT^{-2} * T^2[/tex] --- acceleration * square of time

The expression becomes:

[tex]s = ut + \frac{1}{2}at^2[/tex]

[tex]M^0LT^0 = M^0LT^{-1} * T + M^0LT^{-2} * T^2[/tex]

Apply law of indices

[tex]M^0LT^0 = M^0LT^{-1+1} + M^0LT^{-2+2}[/tex]

[tex]M^0LT^0 = M^0LT^{0} + M^0LT^{0}[/tex]

[tex]M^0LT^0 = M^0LT^{0}[/tex]

Both sides of the equation are equal