Question

At standard temperature, a gas has a volume of 275 mL. The temperature is then increased to
130. C, and the pressure is held constant. What is the new volume?
I

Answer 1

Explanation:

So if V œ T, then V = kT ; if we solve for k under different conditions of volume and temperature......

$\frac{v1}{t1} = \frac{v2}{t2}$

temperature is measured in degrees Kelvin.

And

$v2 = \frac{v1}{t1} \times t2 = \frac{275 . ml}{298 \: . \: k } \times 403 \: . \: k = ?$

?mL

Answer 2

0.403 L is the new volume where the initial volume is 275 mL and the initial temperature is 273 K.

What is gas law?

Gas laws relate to the pressure, volume, and temperature of a gas. Boyle's law—named for Robert Boyle—states that, at constant temperature, the pressure P of a gas varies inversely with its volume V, or PV = k, where k is a constant.

The relationship between volume and temperature is: $\frac{V_1}{T_1} =\frac{V_2}{T_2}$ where $V_1$and $T_1$ are the initial volumes and $V_2$ and $T_2$ are the final volumes.

$\frac{V_1}{T_1} =\frac{V_2}{T_2}$

Given data:

$V_1 =$ 275 mL, $T_1 =$ 0

$V_2 =$ 275 mL, $T_2 =$ 130

Putting all the values in the equation:

$\frac{V_1}{T_1} =\frac{V_2}{T_2}$

$\frac{0.275}{273} =\frac{V_2}{403}$

$V_2 =$ 0.403 L

Hence, 0.403 L is the new volume.

Learn more about gas law here:

https://brainly.com/question/12669509

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