Answer:
The correct answer is - brown heterozygous Bb and blue eye bb.
Explanation:
In the provided question it is given that there are 20 babies born, 10 babies had blue eyes and 10 had brown eyes. As it is known that brown eyes are dominant over blue eyes, therefore, on the basis of this we can say that all blue-eyed babies have a bb genotype and as brown eyes are dominant traits babies must have at least one copy of the B allele which represents brown eye trait.
case1:
Parent 1 : bb
parent 2: BB
B B
b Bb Bb
b Bb Bb
there are 100% brown eye offspring so this is not the case
case 2:
Parent 1 : bb
parent 2: Bb
B b
b Bb bb
b Bb bb
here, 50% brown eyes and 50% blue eyes offspring produced thus, the parent trait will be brown heterozygous and blue eye.
