Question

40 points! and I will mark you Brainliest !
Find the shaded area. Round to the nearest tenth if necessary.

Answer 1

Answer:

1.) 49.5 mm ^2

2.) 183 in. ^ 2

Step-by-step explanation:

So for number one, it's a very irregular shape, but luckily, we can split it vertically! Into a triangle & a quadrilateral.

The area of the quadrilateral would be

6*7 = 42

The triangle is more difficult, because its not directly given, BUT, we do know that the height would have to be 6 minus 3, and the base would be 12 minus 7... So the equation is

$A = \frac{1}{2} bh\\A = \frac{1}{2}(5)(3)\\A = 7.5$

Now, the rectangle and the triangle account for the total area in this case, when you add them, you get 49.5 mm ^2

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For the second, we have a trapezoid with a triangular cutout, the area of a trapezoid is defined as:

$A = \frac{1}{2} (B1-B2) h$

Luckliy, none of the numbers of the bases, or height, are hidden. The height is 18, the larger base is 51, and the smaller is 24.

$A = \frac{1}{2} (51-24)18\\A = 243$

So, the trapezoid area is 243 in ^2. But we aren't done, we still have the triangle! It will be easy though!

Remember, the formula for a triangle is half the base times the height. These numbers are directly given to us!

$A = \frac{1}{2} (12)(9)\\A = 54$

Now, since the triangle is NOT SHADED, we subtract it's area from the trapezoid's...

$243 - 54 = 183$

The area is 183 in. ^ 2

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Answer 2

Answer:

1)49.5mm ^2.

2)183 in ^2.

Step-by-step explanation:

So for number one it's a very iregular shape,but luckily ,we can slip it vertycally.

6×7=42.

The triangle is more difficult because it's not directly given.

The questions is:

A=1 on 2 bh.

A= 1 on 2 (5 and 3)